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NEW QUESTION: 1
<img src="CCIE_RS_400-101_140q-44_18.jpg" width="582" height="360">
Exhibit:
<img src="CCIE_RS_400-101_140q-45_19.jpg" width="582" height="360">
Select and Place:
<img src="CCIE_RS_400-101_140q-45_20.jpg" width="582" height="360">
Answer:
Explanation:
<img src="CCIE_RS_400-101_140q-46_21.jpg" width="582" height="360">
Section: Drag and Drop
Explanation/Reference:
A.
B.
C.
D.

NEW QUESTION: 2


Answer:
Explanation:

Explanation


NEW QUESTION: 3



A. SELECT colors1. Name count (colors2.name)
FROM colors1
INNER JOIN colors2
on colors1. Name =colors2. Name
GROUP BY colors1 .name;
B. SELECT colors1 .name.count (colors2.name)
FROM colors1. Colors2
WHERE
Colors1. Name = (SELECT DISTINCT name FROM colors2 WHERE colors1.name=colors2.name)
GROUP BY colorse1.name,
C. SELECT colors1.name, count (colors2.name)
FROM JOIN colors2
on colors1 .name =colors2.name
GROUP BY colors1.name;
SELECT colors1.name, count (colors2.name)
FROM colors1
RIGHT JOIN colors1
on colors1 .name =colors2.name
GROUP BY colors1.name;
D. SELECT colors1.name, count(colorse2. Name)
FROM colorse1 .name =colors2.name
WHERE colors1. Name =colors2.name
GROUP BY colors1.name,
Answer: C