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NEW QUESTION: 1
Which two may be used to configure InfoSphere MDM Server business rules? (Choose two.)
A. adding entries to the external rule framework database tables
B. adding the appropriate properties files
C. adding entries to the extension framework database tables
D. specifying the rule engine in the Configuration and Management component
Answer: A,C
NEW QUESTION: 2
When should you output your Illustrator document to the EPS file format?
A. when using an EPSF Riders file
B. when you are finished editing vector graphics
C. when creating a Web animation that requires scalable vector graphics and NO additional browser plug-ins
D. whenplacingartwork withbothrastersand vectors into an unknown page layout program
Answer: D
NEW QUESTION: 3
Which three statements correctly describe the relationship amongst jobs, programs, and schedules within the Oracle Job Scheduler? (Choose three.)
A. A program can be used in the definition of multiple jobs.
B. A job is specified as part of a program definition.
C. A program and schedule can be specified as part of a job definition.
D. A program and window can be specified as part of a job definition.
E. A program and job can be specified as part of a schedule definition.
Answer: A,C,D
NEW QUESTION: 4
Which single Cisco IOS ACL entry permits IP addresses from 172.16.80.0 to 172.16.87.255?
A. permit 172.16.80.0 0.0.7.255
B. permit 172.16.80.0 255.255.248.0
C. permit 172.16.80.0 0.0.3.255
D. permit 172.16.80.0 0.0.248.255
E. permit 172.16.80.0 255.255.240.0
F. permit 176.16.80.0 255.255.252.0
Answer: A
Explanation:
www.cisco.com/en/US/products/sw/secursw/ps1018/products_tech_note09186a00800a5b 9a.shtml ACL Summarization Note: Subnet masks can also be represented as a fixed length notation. For example, 192.168.10.0/24 represents 192.168.10.0 255.255.255.0. This list describes how to summarize a range of networks into a single network for ACL optimization. Consider these networks. 192.168.32.0/24 192.168.33.0/24 192.168.34.0/24 192.168.35.0/24 192.168.36.0/24 192.168.37.0/24 192.168.38.0/24 192.168.39.0/24
The first two octets and the last octet are the same for each network. This table is an explanation of how to summarize these into a single network.
The third octet for the previous networks can be written as seen in this table, according to the octet bit position and address value for each bit.
Decimal 128 64 32 16 8 4 2 1 32 0 0 1 0 0 0 0 0 33 0 0 1 0 0 0 0 1 34 0 0 1 0 0 0 1 0 35 0 0 1 0 0 0 1 1 36 0 0 1 0 0 1 0 0 37 0 0 1 0 0 1 0 1 38 0 0 1 0 0 1 1 0 39 0 0 1 0 0 1 1 1 M M M M M D D D
Since the first five bits match, the previous eight networks can be summarized into one network (192.168.32.0/21 or 192.168.32.0 255.255.248.0). All eight possible combinations of the three low-order bits are relevant for the network ranges in question. This command defines an ACL that permits this network. If you subtract 255.255.248.0 (normal mask) from 255.255.255.255, it yields 0.0.7.255. access-list acl_permit permit ip 192.168.32.0 0.0.7.255
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