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820-605 -- Designing Blue Prism Process Solutions

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NEW QUESTION: 1
Select which of the following correctly describes the XML namespace to which the -->(1) "price" element in the "XML Document" below belongs.
[XML Documents]
<?xml version="1. 0"?>
<products xmlns="urn:sample:product">
<item:product xmlns:item="urn:sample:item">
<item:name>T-Shirt</item:name>
<price>2500</price> -->(1) </item:product>
</products>
A. urn:sample:product
B. urn:sample:item
C. None W Courier Newlr Z
D. item
Answer: A

NEW QUESTION: 2
Which two of the following Cisco router platforms support Multicast Distributed Fast Switching? (Choose two.)
A. 7200 series with NSE-1
B. 3600 series
C. 7500 series
D. 12000 series
Answer: C,D
Explanation:
Section: (none)
Explanation/Reference:

NEW QUESTION: 3
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
* Students must be ranked based on their average marks.
* If one or more students have the same average, the same rank must be given to these students.
* Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
C. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
F. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
H. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: E
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/ms189798.aspx