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NEW QUESTION: 1
質問のドラッグアンドドロップ
ファイバーケーブル接続タイプを適切な画像にドラッグアンドドロップします。
Answer:
Explanation:
NEW QUESTION: 2
A. Option C
B. Option D
C. Option B
D. Option A
E. Option E
Answer: C,D,E
NEW QUESTION: 3
What are two advantages of Network I/O Control? (Choose two.)
A. Monitors the virtual machine storage.
B. Enforces traffic isolation.
C. Enforces network bandwidth limit on the virtual distributed switch.
D. Performs load-based teaming.
Answer: C,D
Explanation:
Limits - Enforce traffic bandwidth limit on the overall VDS set of dvUplinks. Load-based Teaming - Efficiently uses a VDS set of dvUplinks for networking capacity. Reference: http://www.vmware.com/products/vsphere/features/network-io-control
NEW QUESTION: 4
You administer a Microsoft SQL Server 2012 database that includes a table named Products. The Products table has columns named Productld, ProductName, and CreatedDateTime.
The table contains a unique constraint on the combination of ProductName and CreatedDateTime.
You need to modify the Products table to meet the following requirements:
- Remove all duplicates of the Products table based on the ProductName column. - Retain only the newest Products row.
Which Transact-SQL query should you use?
A. ProductName = cte.ProductName
B. WITH CTEDupRecords AS ( SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName FROM Products GROUP BY ProductName HAVING COUNT(*) > 1 ) DELETE p FROM Products p JOIN CTEDupRecords cte ON
C. ProductName = cte.ProductName AND p.CreatedDateTime > cte.CreatedDateTime
D. WITH CTEDupRecords AS ( SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName FROM Products GROUP BY ProductName HAVING COUNT(*) > 1 ) DELETE p FROM Products p JOIN CTEDupRecords cte ON
E. WITH CTEDupRecords AS ( SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName FROM Products GROUP BY ProductName HAVING COUNT(*) > 1 ) DELETE p FROM Products p JOIN CTEDupRecords cte ON cte.ProductName = p.ProductName AND cte.CreatedDateTime > p.CreatedDateTime
F. WITH CTEDupRecords AS ( SELECT MIN(CreatedDateTime) AS CreatedDateTime, ProductName FROM Products GROUP BY ProductName ) DELETE p FROM Products p JOIN CTEDupRecords cte ON
G. ProductName = cte.ProductName
Answer: C
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