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NEW QUESTION: 1
An A/R invoice was added to the system but an inventory transaction was NOT created.
What could be the reasons?
A. The in-stock quantity of the items falls below the minimum level
B. The invoke is based on a delivery document
C. The items in the invoice are missing the unit of measure group
D. The customer has exceeded their credit limit
Answer: B
NEW QUESTION: 2
The SAP on PE-A has been configured with dot1q encapsulation. The SAP on PE-B has been configured with qinq encapsulation. CE-A sends frames with a single tag of 100. The VLAN tag from CE-A must be passed transparently. CE-B is expecting a frame with a top tag of 200 and bottom tag of 100. Which of the following is the correct SAP id for PE-B?
A. sap 1/1/1:200*
B. sap 1/1/1:200.100
C. sap 1/1/1:*
D. sap 1/1/1:0*
Answer: A
NEW QUESTION: 3
A. 0
B. 1
C. 2
D. 3
E. 4
Answer: D
Explanation:
Explanation
Each octet represents eight bits. The bits, in turn, represent (from left to right): 128, 64, 32 , 16 , 8, 4, 2, 1 Add them up and you get 255. Add one for the all zeros option, and the total is 256.
Now, take away one of these for the network address (all zeros) and another for the broadcast address (all ones). Each octet represents 254 possible hosts. Or 254 possible networks. Unless you have subnet zero set on your network gear, in which case you could conceivably have 255.
The CIDR addressing format (/20) tells us that 20 bits are used for the network portion, so the maximum number of networks are 2