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NEW QUESTION: 1
View the Exhibit and examine the data in the PROMO_NAME and PROMO_END_DATE columns of the PROMOTIONS table, and the required output format.
Which two queries give the correct result? (Choose two.)
A. SELECT promo_name,TO_CHAR (promo_end_date,'fxDay') ', '
TO_CHAR(promo_end_date,'fxMonth') ' '
TO_CHAR(promo_end_date,'fxDD, YYYY') AS last_day
FROM promotions;
B. SELECTpromo_name,TO_CHAR(promo_end_date,'fmDay')','
TO_CHAR(promo_end_date,'fmMonth') ' '
TO_CHAR(promo_end_date,'fmDD, YYYY') AS last_day
FROM promotions;
C. SELECT promo_name, TO_CHAR(promo_end_date,'Day') ', '
TO_CHAR(promo_end_date,'Month') ' '
TO_CHAR(promo_end_date,'DD, YYYY') AS last_day
FROM promotions;
D. SELECT promo_name, TRIM(TO_CHAR(promo_end_date,'Day')) ', ' TRIM(TO_CHAR
(promo_end_date,'Month')) ' '
TRIM(TO_CHAR(promo_end_date,'DD, YYYY')) AS last_day
FROM promotions;
Answer: B,D
NEW QUESTION: 2
In a large metropolitan area, past records revealed that 30 percent of all the high school graduates go to college. From 20 graduates selected at random, what is the probability that exactly 8 will go to college?
A. 0.114
B. 0.231
C. 0.400
Answer: A
Explanation:
This is a binomial probability. The probability of getting r successes out of n trials where the probability of success each trial is p and probability of failure each trial is q (where q = 1-p) is given by:
r (n-r)
n!(p )[q ]/[r!(n-r)!]. Here n = 20, r = 8,p = 0.3 and q = 0.7.
8 12
Therefore we have 20!(0.3 )(0.7 )/[8!12!] = 0.114.
NEW QUESTION: 3
組織のプライバシープログラムの確立を支援する上で、内部監査の適切な役割は次のうちどれですか？
A. 新しい規制によってもたらされるリスクの分析
B. プライバシーに関連する組織内の役割の定義
C. 個人データを保護するためのコントロールの設計
D. 個人データの使用を監視するための手順の開発
Answer: D
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