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NEW QUESTION: 1
ASP.NETアプリケーションを実行するAzure仮想マシンをデプロイします。アプリケーションは、会社のユーザーがインターネットからアクセスします。
ユーザーがASP.NETアプリケーションに接続する前に、Azure Active Directory(Azure AD)アカウントを使用して事前認証されていることを確認するためのソリューションを推奨する必要があります。推奨には何を含める必要がありますか?
A. Azure Application Gateway
B. パブリックAzureロードバランサー
C. AzureADエンタープライズアプリケーション
D. Azure Traffic Manager
Answer: C
Explanation:
You can manage service principals in the Azure portal through the Enterprise Applications experience. Service principals are what govern an application connecting to Azure AD and can be considered the instance of the application in your directory.
Reference:
https://docs.microsoft.com/en-us/azure/active-directory/develop/active-directory-how-applications-are-added

NEW QUESTION: 2
When Jason moves a file via NFS over the company's network, you want to grab a copy of it by sniffing. Which of the following tool accomplishes this?
A. nfscopy
B. webspy
C. filesnarf
D. macof
Answer: C
Explanation:
Filesnarf - sniff files from NFS traffic OPTIONS -i interface Specify the interface to listen on.
-v "Versus" mode. Invert thesenseofmatching,to select non-matching files.
Pattern
Specify regular expression for filename matching.
Expression
Specifyatcpdump(8)filter expression to selecttraffic to sniff.
SEE ALSO
Dsniff,nfsd

NEW QUESTION: 3
Given: Given:
public class SuperTest {
public static void main(String[] args) { statement1 statement2 statement3
}
}
class Shape {
public Shape() {
System.out.println("Shape: constructor");
}
public void foo() {
System.out.println("Shape: foo");
}
}
class Square extends Shape {
public Square() {
super();
}
public Square(String label) {
System.out.println("Square: constructor");
}
public void foo() {
super.foo();
}
public void foo(String label) {
System.out.println("Square: foo");
}
}
}
}

Shape: constructor
Square: foo
Shape: foo
A. Square square = new Square ("bar");
square.foo ("bar");
square.foo ("bar");
B. Square square = new Square ("bar");
square.foo ("bar");
square.foo();
C. Square square = new Square ();
square.foo ();
square.foo(bar);
D. Square square = new Square();
square.foo("bar");
square.foo();
E. Square square = new Square ();
square.foo ();
square.foo("bar");
F. Square square = new Square ();
square.foo ();
square.foo ();
Answer: D

NEW QUESTION: 4
How granular may an administrator filter an Access Role with identity awareness? Per:
A. Windows Domain
B. Radius Group
C. Specific ICA Certificate
D. AD User
Answer: D