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NEW QUESTION: 1
In Huawei FusionCompute, if the Windows virtual machine has a blue screen, what operations can the system perform? [Multiple choice]
A. Not processed
B. Recover a virtual machine using a snapshot
C. HA Virtual Machine
D. Restart the virtual machine
Answer: A,C,D
NEW QUESTION: 2
管理されていないパッケージにはロックされたコンポーネントは含まれていませんが、アップグレードできますか?
A. 偽
B. 本当
Answer: A
NEW QUESTION: 3
キオスクという名前のクラスを含むアプリケーションを開発しています。 Kioskクラスには、Catalogという名前の静的プロパティが含まれています。 キオスククラスは、次のコードセグメントで定義されます。 (行番号は参照用にのみ記載されています)。
あなたには次の要件があります。
* Catalogインスタンスに_catalogフィールドを初期化します。
* _catalogフィールドは一度しか初期化しないでください。
* _catalogオブジェクトをインスタンス化する必要がある場合のみ、アプリケーションコードがロックを取得するようにしてください。
あなたは要件を満たす必要があります。
どの3つのコードセグメントを09行目に順番に挿入しますか? (答えは、適切なコードセグメントをコードセグメントのリストからアンサーエリアに移動し、正しい順序で並べ替えることです)。
Answer:
Explanation:
Explanation
After taking a lock you must check once again the _catalog field to be sure that other threads didn't instantiated it in the meantime.
NEW QUESTION: 4
A. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10, 00:00:16, FastEthemet0/0
B. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
C. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
D. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10, 00:00:16, Serial1/0
Answer: B
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore the cost is 12 (learned from Router_A) + 1 = 13 for both subnets -> The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0. In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.