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NEW QUESTION: 1
If the user wants to query the historical alarm service in the last 7 days, what services need to be opened?
A. Elastic Cloud Hosting Service
B. Cloud Audit Service
C. Relational database services
D. Message Notification Service
Answer: B
NEW QUESTION: 2
Note: This question is part of a series of a questions that present the same scenario. Each question in the series contains a unique solution that might meet the stated goals. Some questions sets might have more than one correct solutions, while others might not have a correct solution.
After you answer a question in this section, you will NOT be able to return to it. As a result, these questions will not appear in the review screen.
Your network contains an Active Directory forest named contoso.com. The forest contains a member server named Server1 that runs Windows Server 2016. All domain controllers run Windows Server 2012 R2.
Contoso.com has the following configuration.
You plan to deploy an Active Directory Federation Services (AD FS) farm on Server1 and to configure device registration.
You need to configure Active Directory to support the planned deployment.
Solution: You upgrade a domain controller to Windows Server 2016.
Does this meet the goal?
A. No
B. Yes
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Device registration requires a forest functional level of Windows Server 2012 R2.
References:
https://technet.microsoft.com/en-us/windows-server-docs/identity/ad-fs/deployment/configure-a-federation- server-with-device-registration-service
https://technet.microsoft.com/en-us/windows-server-docs/identity/ad-fs/design/ad-fs-requirements
NEW QUESTION: 3
Refer to the exhibit. Why is the 140.140.0.0 network not used as the gateway of last resort even though it is configured first?
R3#show run | include defaultip default-network 140.140.0.0
ip default-network 130.130.0.0
R3#show ip route | begin Gateway
Gateway of last resort is 0.0.0.0 to network 130.130.0.0
116.0.0.0/8 is variably subnetted, 5 subnets, 3 masks
C 116.16.37.0/30 is directly connected, Serial1/0.2
C 116.16.32.0/30 is directly connected, Serial2/0.2
C 116.16.34.0/28 is directly connected, Serial1/0.1
C 116.16.35.0/28 is directly connected, Serial2/0.1
S 116.0.0.0/8 [1/0] via 116.16.34.0
* 140.140.0.0/32 is subnetted, 3 subnets
O 140.140.1.1 [110/65J via 116.16.34.4, 00:14:54, Serial1/0.1
O 140.140.3.1 [110/65] via 116.16.34.4, 00:14:54, Serial1/0.1
O 140.140.2.1 [110/65] via 116.16.34.4, 00:14:54, Serial1/0.1
* 130.130.0.0/16 is variably subnetted, 4 subnets, 2 masks
D* 130.130.0.0/16 is a summary, 00:30:04, Null0
C 130.130.1.0/24 is directly connected, Ethernet0/0
C 130.130.2.0/24 is directly connected, Ethernet0/1
C 130.130.3.0/24 is directly connected, Ethernet1/0
D 150.150.0.0/16 [90/679936] via 116.16.35.5, 00:02:58, Serial2/0.1
A. The last default-network statement will always be preferred.
B. A router will load balance across multiple default-networks; repeatedly issuing the show ip route command would show the gateway of last resort changing between the two networks.
C. Default-network selection will always prefer the statement with the lowest IP address.
D. A route to the 140.140.0.0 network does not exist in the routing table.
Answer: D
Explanation:
In the routing table of R3, we can only see the route 130.130.0.0/16 is learned via EIGRP (marked with D) and is being chosen as the "Gateway of last resort".
The route to 140.140.0.0 is not present in the routing table so the command "ip default-network
140.140.0.0" has no effect.
Remember that a route must appear in the routing table (via static route or learned via a routing protocol before it can be set as "Gateway of last resort" by the "ip default-network" command.
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