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NEW QUESTION: 1
As an HR Professional, you must sometimes terminate employees from your organization. When an employee is terminated, there must be a just cause or a good cause for the termination. Which one of the following is not a valid just cause for the employee's termination?
A. Whether the rule has been applied consistently
B. Whether reasonable "proof" of the violation existed, or was obtained through investigation
C. Whether the employee was warned in advance
D. Whether the employee is a member of a protected class
Answer: D
Explanation:
Explanation/Reference:
Answer option D is correct.
The membership of a protected class should have no bearing on a good cause for termination.
Answer options B, A, and C are incorrect. These are examples of just cause of termination.
Reference: PHR Exam Prep, Pearson Education, ISBN: 978-0-7897-3677-2. Chapter Seven: Employee and Labor Relations. Official PHR and SPHR Certification Guide, HR Certification Institute, ISBN: 978-1-
586-44149-4, Section III, The US HR Body of Knowledge.
Chapter: Employee and Labor Relations
Objective: Employee Relations
NEW QUESTION: 2
Your network contains an Active Directory forest named contoso.com. All servers run Windows Server 2012.
You need to create a custom Active Directory application partition.
Which tool should you use?
A. Netdom
B. Dsadd
C. Ntdsutil
D. Dsmod
Answer: C
Explanation:
* To create or delete an application directory partition Open Command Prompt.
Type:ntdsutil
At the ntdsutil command prompt, type:domain management At the domain management command prompt,
type:connection At the server connections command prompt, type:connect to server ServerName At the
server connections command prompt, type:quit At the domain management command prompt, do one of
the following:
*partition management Manages directory partitions for Active Directory Domain Services (AD DS) or Active Directory Lightweight Directory Services (AD LDS). This is a subcommand of Ntdsutil and Dsmgmt. Ntdsutil and Dsmgmt are command-line tools that are built into Windows Server 2008 and Windows Server 2008 R2. / partition management create nc %s1 %s2 Creates the application directory partition with distinguished name %s1, on the Active Directory domain
controller or AD LDS instance with full DNS name %s2. If you specify "NULL" for %s2, this command uses
the currently connected Active Directory domain controller.
Use this command only with AD DS. For AD LDS, use create nc %s1 %s2 %s3.
Note:
*An application directory partition is a directory partition that is replicated only to specific domain controllers. A domain controller that participates in the replication of a particular application directory partition hosts a replica of that partition.
NEW QUESTION: 3
ユーザーが別の建物のサーバーに接続できません。技術者が問題のトラブルシューティングを行っており、次のことを確認しています。
1)192.168.10.25/25の場合、クライアントPC 1にはIPアドレスがあります
2)PC 1は、192.168.10.1 / 25のゲートウェイに正常にpingできます。
ルータAのインターフェース
3)サーバーAの名前は「BLDGBFILESRVR01」で、IPアドレスは
192.168.10.145/25
4)IPアドレスが192.168.10.200/25のPC 2は正常にpingできます
サーバーA
ただし、PC 1がサーバーAにpingを送信すると、サーバーAは、到達不能なホストからの応答を受け取ります。次のうちどれが最も可能性の高い原因ですか?
A. Link from PC 1 to router A has duplex issues
B. Link from server A top PC 2 is down
C. Link from router A to server A is down
D. Link from touter A to PC 1 are on different subnets
Answer: D
NEW QUESTION: 4
The management of Intelligent Semiconductor is considering the creation of a new manufacturing facility.
The following information applies to the new facility:
Initial investment outlay: ($50,200,000)
t1: ($3,000,000)
t2: ($1,500,000)
t3: $12,000,000
t4: $20,000,000
t5: $25,000,000
t6: $25,000,000
t7: $20,000,000
t8: ($1,500,000)
t9: ($3,000,000)
t10: $500,000
Assuming a 15% discount rate, along with a $0.00 salvage value at the end of year 10, what is the Modified Internal Rate of Return for this project?
A. 12.66%
B. Because this is a non-normal project, the Modified Internal Rate of Return cannot be calculated.
C. 14.61%
D. 9.88%
E. 13.90%
F. 13.19%
Answer: E
Explanation:
Explanation/Reference:
Explanation:
Remember that the Modified Internal Rate of Return escapes many of the pitfalls associated with the traditional Internal Rate of Return calculation. One such pitfall is the fact that the traditional IRR cannot produce reliable calculations for "non-normal" projects, such as the project illustrated in this example. The Modified Internal Rate of Return, however, escapes this basic flaw and can be used to evaluate virtually any project. The calculation of the answer in this example is as follows:
Step 1: Determine the Future Value of the cash inflows by compounding each positive inflow by the cost of capital. This value is often referred to as the "Terminal Value." Remember that in this example, the positive cash inflows begin at period 3.
Step 2: Determine the Present Value of the cash outflows by discounting each negative inflow by the cost of capital. The cash inflows to be discounted occur in periods 1, 2, 8, and 9.
Step 3: Determine the rate that equates the PV of the cash outflows to the FV of the cash inflows. The calculation of the FV of the cash inflows is shown as follows:
FV of the cash inflows = {[$12,000,000 * 2.660] + [$20,000,000 * 2.313] + [$25,000,000 * 2.011] +
[$25,000,000 * 1.749] + [$20,000,000 * 1.521] + [$500,000 * 1]} = $203,100,000.
This is the terminal value.
The calculation of the PV of the cash outflows is calculated as follows:
PV of the cash outflows = {$50,200,000 + [$3,000,000 / 1.15] + [$1,500,000 /1.323] + [$1,500,000 / 3.059]
+ [$3,000,000 / 3.518]} = $55,285,596.07
Now that the present and future (terminal) values of the cash flows have been determined, the Modified Internal Rate of Return can take place. The following values are imputed into the Present Value worksheet on your calculator:
PV =($55,285,596), FV = $203,100,000, N = 10, PMT = $0.00, Compute I Imputing these values will yield an answer of 13.896% for the Modified Internal Rate of Return.