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NEW QUESTION: 1
You have a server named Server1 that runs Windows Server 2016. Server1 has four SCSI disks and a storage pool named Pool1 that contains three disks.
You create a virtual disk named Disk 1 that uses a mirrored layout.
You create a partition named Partition1 that uses all of the available space on Disk 1.
You need to extend Partition1.
What should you do first?
A. From Windows PowerShell, run the Resize-Partition cmdlet.
B. From Windows PowerShell, run the Resize-StorageTier cmdlet.
C. From Disk Management, extend a volume.
D. From the Storage Pools page in Server Manager, extend a virtual disk.
Answer: D
Explanation:
References: https://charbelnemnom.com/2015/03/step-by-step-how-to-extend-and-resize-a-two-way-mirrored-storage-tiered-space-storagespaces-ws2012r2/
NEW QUESTION: 2
展示を参照してください。 show ip ospf interfaceコマンドがR1で実行されましたOSPFはどのように設定されますか？
A. A point-to-point network type is configured
B. The default Hello and Dead timers are in use
C. The interface is not participating in OSPF
D. There are six OSPF neighbors on this interface
Answer: B
Explanation:
From the output we can see there are Designated Router & Backup Designated Router for this OSPF domain so this is a broadcast network (point-to-point and point-to-multipoint networks do not elect DR & BDR) -> Answer B is not correct.
By default, the timers on a broadcast network (Ethernet, point-to-point and point-to-multipoint) are 10 seconds hello and 40 seconds dead (therefore answer C is correct). The timers on a non-broadcast network are 30 seconds hello
120 seconds dead.
From the line "Neighbor Count is 3", we learn there are four OSPF routers in this OSPF domain -> Answer D is not correct.
NEW QUESTION: 3
A. Option
B. Option
C. Option
D. Option
Answer: A
NEW QUESTION: 4
What can be said about observations of random variables that are i.i.d. a normally distributed?
A. The estimated mean divided by the estimated standard deviation has a t-distribution
B. The estimated mean divided by the estimated standard deviation has a Chi2-distribution
C. The estimated mean divided by the estimated variance has a Chi2-distribution
D. The estimated mean divided by the estimated variance has a t-distribution
Answer: A
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